If it's not what You are looking for type in the equation solver your own equation and let us solve it.
31n^2-10n=0
a = 31; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·31·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*31}=\frac{0}{62} =0 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*31}=\frac{20}{62} =10/31 $
| 15x+24x+21x=180 | | −4x−6=-3x-10−3x−10 | | -7(q+1)=35 | | t+11/12=11/8 | | x+8=11-3x | | 2x=93+28x-13 | | q^2-8q-45=0 | | 2y+19=9 | | X+2/4=-5x+2 | | 4x−5=17 | | 4+6y=40 | | 8x-2+15x=180 | | X*1.06=x+15 | | 7/9x=62/9 | | 2(=w+7)+6(3w−1) | | 90=(0.85)(80.11)+(0.15)(x) | | .25x-7/4=1+3x | | y^2=12y=36 | | x/2-15=25 | | 4x-28=3x+1 | | 3x+4x+4=-19+2 | | 1=1/3z | | 1/3x+1=5-x | | 47-2x=5-2x | | 110=1/2h(2+9) | | 8y=5y-24 | | 2x/7=x-1/3 | | 2x+4=5x-8= | | 4y=12y-48 | | (x+2)(x-5)=(x+1)(x+1)-10 | | -2k-15=6 | | 6x-22=2x-6 |